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    The 3n + 1 problem
100.c
/* Trivial */
#include <stdio.h>
int algorithm(int n)
{
	int length=1;
	while(n!=1) {
		if (n%2) {
			n = 3*n+1;
		} else {
			n = n/2;
		}
		length++;
	}
	return length;
}
#define MIN(a,b) ((a) < (b) ? (a) : (b))
#define MAX(a,b) ((a) > (b) ? (a) : (b))
int main()
{
	int i,j;
	while(scanf("%d %d", &i, &j)==2) {
		int n;
		int maximum=0;
		for(n=MIN(i,j); n<=MAX(i,j); n++) {
			int a = algorithm(n);
			maximum = (maximum>a) ? maximum : a;
		}
		printf("%d %d %d\n", i, j, maximum);
	}
	exit(0);
}
      









